I found that i love math very much recently...however i dont know that i can really make money with mathematic as it seen not contribute a lot of cash generation..
here some funny story:
Q: How does one insult a mathematician?
A: You say: "Your brain is smaller than any
here some funny story:
Q: How does one insult a mathematician?
A: You say: "Your brain is smaller than any
ε > 0"
An engineer thinks that his equations are an approximation to reality.
A physicist thinks reality is an approximation to his equations.
A mathematician doesn't care.
wat u say to ur honey through math..
1. Honey, you're sweeter than 3.14
2. I'm not trying to be obtuse, but you're acute girl.
3. You and I would add up better than a Riemann sum.
4. I'll love you from here to infinity
5. You fascinate me more then the Fundamental Theorem of Calculus.
6. Are you a differential function? Because I'd like to be tangent to your curves!
7. I am equivalent to the Empty Set when you aren't with me.
want know who is my honey ? solve x, y and z...
1) x={sin[tan-1(sin@/cos@)]/cos[tan-1(sin@/cos@)]} /@
(@ considered as variable too)
2) y=((l+a)^2)e - (l+a)(l-a)e- 2e(a^2)
3) z= {(p-1)(e-1)+(p+e)][(n+1)(g-1)+(n-g)]+[1+ep-gn]
so she is x y z
guess it?? haha ,, it is quite easy!!
An engineer thinks that his equations are an approximation to reality.
A physicist thinks reality is an approximation to his equations.
A mathematician doesn't care.
wat u say to ur honey through math..
1. Honey, you're sweeter than 3.14
2. I'm not trying to be obtuse, but you're acute girl.
3. You and I would add up better than a Riemann sum.
4. I'll love you from here to infinity
5. You fascinate me more then the Fundamental Theorem of Calculus.
6. Are you a differential function? Because I'd like to be tangent to your curves!
7. I am equivalent to the Empty Set when you aren't with me.
want know who is my honey ? solve x, y and z...
1) x={sin[tan-1(sin@/cos@)]/cos[tan-1(sin@/cos@)]} /@
(@ considered as variable too)
2) y=((l+a)^2)e - (l+a)(l-a)e- 2e(a^2)
3) z= {(p-1)(e-1)+(p+e)][(n+1)(g-1)+(n-g)]+[1+ep-gn]
so she is x y z
guess it?? haha ,, it is quite easy!!
1 comment:
for the "x"
answer I got is
tan(tan-tan@)/@
"and I assume that TAN is independent from Tangent"
for the "y" I totally got blur
e(l)^2 + 2ael +(a)^2 e + l^2
for the "x" is clearly known
peng
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